If 2 mole of an ideal monoatomic gas at temperature T, is mixed with 6 mole of another ideal monoatomic gas at temperature 2T then the temperature of mixture is :
- 52T
- 54T
- 72T
- 74T
Answer
(4) 74T
Solution
No heat is lost and no work is done on mixing ⇒ total internal energy is conserved.
For a monoatomic gas U= 32nRT
32R(2)(T)+ 32R(6)(2T)= 32R(2+6) Tmix
⇒ Tmix= 2T+12T8= 14T8
∴ Tmix= 74T
Answer: (4)