A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25 106 m above the surface of earth. If earth's radius is 6.38 106 m and g = 9.8 m s-2, then the orbital speed of the satellite is
- 9.13 km s-1
- 6.67 km s-1
- 7.76 km s-1
- 8.56 km s-1
Answer
(3) 7.76 km s-1
Solution
Orbital speed: v0 = GMERE + h = gRE2RE + h
RE + h = 6.38 106 + 0.25 106 = 6.63 106 m
v0 = 9.8 (6.38 106)26.63 106
= 6.02 107 m s-1
7.76 103 m s-1 = 7.76 km s-1
Answer: (3)