In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2 V, what is the wavelength of the em-wave? (Given hc=1242 eV nm where h is the Planck's constant and c is the speed of light in vacuum.)
- 400 nm
- 600 nm
- 300 nm
- 200 nm
Answer
(3) 300 nm
Solution
Einstein: hc = +eV0=2.14+2=4.14 eV
= 12424.14=300 nm
Answer: (3)