A stone of mass 900 g is tied to a string and moved in a vertical circle of radius 1 m making 10 rpm. The tension in the string, when the stone is at the lowest point is (if 2=9.8 and g=9.8 m/s2) :
- 17.8 N
- 97 N
- 9.8 N
- 8.82 N
Answer
(3) 9.8 N
Solution
[figure]
m=0.9 kg, = 2 N60= 2 1060= 3 rad/s
Lowest point: T-mg=m 2r
T=0.9 9.8+0.9 29 1
=8.82+0.9 9.89=8.82+0.98=9.8 N
At the lowest point T acts up, mg down; their difference gives the centripetal force.
Answer: (3)