A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? ( = 3.14)
- 0.5024 V
- 0.0628 V
- 0.2512 V
- 0.1256 V
Answer
(3) 0.2512 V
Solution
An element dr at distance r moves with speed r:
d = B( r) dr
= 0R B r dr = 12B R2
= 12 0.4 10 (0.2)2
= 0.08 = 0.08 3.14 = 0.2512 V
Answer: (3)