A particle oscillates along the x-axis according to the law, x(t)=x0 2 ( t2 ) where x0=1 m. The kinetic energy (K) of the particle as a function of x is correctly represented by the graph
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Answer
(4) [figure]
Solution
x= 1- t2 v= t2, and 2t=1-(1-2x)2=4x(1-x)
K= 12mv2= m8 2t= m2 x(1-x)
Downward parabola: K=0 at x=0,1 (extremes), maximum m8 at x= 12
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Answer: (4)