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Electrostatic Potential and Capacitance · Question 43

JEE Main 2025 (Online) 28th January Evening ShiftMCQEasy📈 Topic in 13% papers+4−1
1

A parallel plate capacitor of capacitance 1 μF is charged to a potential difference of 20 V. The distance between plates is 1 μm. The energy density between plates of capacitor is :

  1. 1.8 103 J/m3
  2. 2 102 J/m3
  3. 2 10-4 J/m3
  4. 1.8 105 J/m3

Answer

(1) 1.8 103 J/m3

Solution

Field between the plates: E = Vd = 2010-6 = 2 107 V/m

Energy density: u = 12 0 E2

u = 12 8.85 10-12 (2 107)2

u = 1.77 103 1.8 103 J/m3

Answer: (1)

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2

An electric dipole of dipole moment 6 10-6 C m is placed in uniform electric field of magnitude 106 V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be J.

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