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Thermodynamics (Physics)

JEE Main 2025 (Online) 23rd January Morning ShiftNumericalEasy📈 Topic in 50% papers+4
Ques. 1JEE Main 2025, 23 January (Morning Shift)

An ideal gas initially at 0 temperature, is compressed suddenly to one fourth of its volume. If the ratio of specific heat at constant pressure to that at constant volume is 3/2, the change in temperature due to the thermodynamic process is K.

Answer

273

Solution

Sudden compression: no time for heat flow adiabatic, TV -1= constant.

[figure]

Tf=Ti ( ViVf ) -1=273 41/2=546 K

T=546-273=273 K

Answer: 273

Keep practising — Thermodynamics (Physics)

Ques. 2JEE Main 2025, 23 January (Evening Shift)

Water of mass m gram is slowly heated to increase the temperature from T1 to T2. The change in entropy of the water, given specific heat of water is 1 J kg-1 K-1, is :

  1. m(T2-T1)
  2. zero
  3. m ( T1T2 )
  4. m ( T2T1 )
Ques. 3JEE Main 2025, 23 January (Evening Shift)

[figure] Using the given P-V diagram, the work done by an ideal gas along the path ABCD is :

  1. 3P0 V0
  2. -3P0 V0
  3. -4P0 V0
  4. 4P0 V0
Ques. 4JEE Main 2025, 22 January (Evening Shift)

Given are statements for certain thermodynamic variables, Choose the correct answer from the options given below :

  1. C and D Only
  2. A and B Only
  3. D and A Only
  4. B and C Only

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