A bar magnet having a magnetic moment of 2 104 J T-1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 10-4 T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60 from the field is
- 12 J
- 6 J
- 2 J
- 0.6 J
Answer
(2) 6 J
Solution
Work done in turning a magnetic dipole from 1 to 2:
W = mB( 1 - 2)
= (2 104)(6 10-4)( 0 - 60 )
= 12 (1 - 12 )
= 6 J
Answer: (2)