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Alternating Current

JEE Main 2025 (Online) 24th January Morning ShiftMCQEasy📈 Topic in 13% papers+4−1
Ques. 1JEE Main 2025, 24 January (Morning Shift)

An alternating current is given by I=IA t+IB t. The r.m.s current will be

  1. IA2+IB22
  2. IA2+IB22
  3. |IA+IB| 2
  4. IA2+IB2

Answer

(2) IA2+IB22

Solution

I=IA t+IB t=I0 ( t+ ):

[figure]

I0= IA2+IB2 and Irms= I0 2= IA2+IB22

Answer: (2)

Keep practising — Alternating Current

Ques. 2JEE Main 2025, 23 January (Evening Shift)

In a series LCR circuit, a resistor of 300 , a capacitor of 25 nF and an inductor of 100 mH are used. For maximum current in the circuit, the angular frequency of the ac source is 104 radians s-1

Ques. 3JEE Main 2025, 22 January (Evening Shift)

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0. If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be

  1. I02
  2. I0 2
  3. 2I0
  4. I0

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