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Two soap bubbles of radius 2 cm and 4 cm , respectively, are in contact with each other. The radius of curvature of the common surface, in cm , is .
4
The smaller bubble has the higher pressure, so the common film bulges into the larger bubble.
[figure]
P1-P0= 4Sr1, P2-P0= 4Sr2, P1-P2= 4Sr
1r= 1r1- 1r2= 12- 14= 14
r=4 cm
Answer: 4
A tube of length L is shown in the figure. The radius of cross section at the point (1) is 2 cm and at the point (2) is 1 cm , respectively. If the velocity of water entering at point (1) is 2 m/s, then velocity of water leaving the point (2) will be [figure]
A small rigid spherical ball of mass M is dropped in a long vertical tube containing glycerine. The velocity of the ball becomes constant after some time. If the density of glycerine is half of the density of the ball, then the viscous force acting on the ball will be (consider g as acceleration due to gravity)