When a metal surface is illuminated by light of wavelength , the stopping potential is 8 V. When the same surface is illuminated by light of wavelength 3 , stopping potential is 2 V. The threshold wavelength for this surface is:
- 3
- 9
- 5
- 4.5
Answer
(2) 9
Solution
Einstein's equation: eV0= hc - hc 0
8e= hc - hc 0 …(i)
2e= hc3 - hc 0 …(ii)
(i) − (ii): 6e= 23 hc hc =9e
In (i): hc 0=9e-8e=e= 19 hc
0=9
Answer: (2)