For a black body at temperature 727 , its radiating power is 60 watt and temperature of surrounding is 227 . If temperature of black body is changed to 1227 then its radiating power will be
- 304 W
- 320 W
- 240 W
- 120 W
Answer
(2) 320 W
Solution
Net power radiated by a black body in surroundings at T0: P = A(T4 - T04)
T1 = 1000 K, T2 = 1500 K, T0 = 500 K
P2P1 = 15004 - 500410004 - 5004
= 5004(81 - 1)5004(16 - 1) = 8015 = 163
P2 = 60 163 = 320 W
Answer: (2)