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Electrostatic Potential and Capacitance

JEE Main 2024 (Online) 27th January Evening ShiftMCQEasy📈 Topic in 3% papers+4−1
Ques. 1JEE Main 2024, 27 January (Evening Shift)

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. (A) is correct but (R) is not correct
  3. Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  4. (A) is not correct but (R) is correct

Answer

(1) Both (A) and (R) are correct and (R) is the correct explanation of (A)

Solution

W=q(VA-VB)=0 on an equipotential surface (VA=VB) (A) is correct

E has no component along an equipotential surface E surface (R) is correct

F=q E displacement W=Fs 90 =0 (R) explains (A)

Answer: (1)

Keep practising — Electrostatic Potential and Capacitance

Ques. 2JEE Main 2024, 27 January (Evening Shift)

The electric potential at the surface of an atomic nucleus (z=50) of radius 9 10-13 cm is 106 V.

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