When one moves from a point 16 km below the earth's surface to a point 16 km above the earth's surface, the change in g is approximately %. The value of is . (Take radius of the earth = 6400 km.)
- 0.12
- 0.25
- 0.50
- 0.75
Answer
(2) 0.25
Solution
At depth d=16 km: g1=g (1- dR )=g (1- 166400 )=g(1-0.0025)
At height h=16 km (h R): g2 g (1- 2hR )=g (1- 326400 )=g(1-0.005)
∴ Percentage change = g1-g2g 100=(0.005-0.0025) 100
⇒ 0.25
Answer: (2)