In Young's double slit experiment, light from two identical sources are superimposing on a screen. The path difference between the two lights reaching at a point on the screen is 7 /4. The ratio of intensity of fringe at this point with respect to the maximum intensity of the fringe is :
- 12
- 34
- 13
- 14
Answer
(1) 12
Solution
Phase difference: = 2 x= 2 7 4= 7 2
Identical sources: I=I 2 2
II = 2 7 4
= 2 (2 - 4 )= 2 4= 12
Answer: (1)