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Ray Optics and Optical Instruments

JEE Main 2025 (Online) 22nd January Morning ShiftNumericalHard📈 Topic in 26% papers+4
Ques. 1JEE Main 2025, 22 January (Morning Shift)

The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature R=2 m. Another car approaches him from behind with a uniform speed of 90 km/hr. When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the car in the side view mirror is ' a '. The value of 100a is m/s2.

Answer

8

Solution

Convex mirror: f= R2=1 m, vO=25 m/s, u=-24 m; the image is virtual, behind the mirror (figure not to scale).

[figure]

Differentiate 1v+ 1u= 1f: vI=- f2(u-f)2 vO

Differentiate again (vO constant): a= 2f2vO2(u-f)3

|a|= 2 1 252253=0.08 m/s2

100a=8

Answer: 8

Keep practising — Ray Optics and Optical Instruments

Ques. 2JEE Main 2025, 22 January (Evening Shift)

A symmetric thin biconvex lens is cut into four equal parts by two planes AB and CD as shown in figure. If the power of original lens is 4D then the power of a part of the divided lens is [figure]

  1. 2D
  2. 8D
  3. 4D
  4. D

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