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Electric Charges and Fields · Question 31

AIPMT 2003MCQEasy📈 Topic in 25% papers+4−1
1

An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The Coulomb force F between the two is

  1. K e2r2 r
  2. -K e2r3 r
  3. K e2r3 r
  4. -K e2r2 r

Answer

(4) -K e2r2 r

Solution

By Coulomb's law, force on the electron (charge −e) due to the nucleus (charge +e) at distance r:

F = K (+e)(-e)r2 r = -K e2r2 r

where r is the unit vector from the nucleus towards the electron and K = 14 0.

The negative sign shows the force is attractive (towards the nucleus); it varies as 1r2, not 1r3.

Answer: (4)

AIPMT 2003

Keep practising — Electric Charges and Fields

2

A dipole of dipole moment p is placed in uniform electric field E then torque acting on it is given by

  1. = p E
  2. = p E
  3. = p + E
  4. = p - E
AIPMT 2001
3

A charge Q is placed at the centre of a cube, the flux coming out from each face will be

  1. Q6 0 10-6
  2. Q6 0 10-3
  3. Q24 0
  4. Q8 0
AIPMT 2001
4

A charge Q is situated at the corner of a cube, the electric flux passed through all the six faces of the cube is

  1. Q6 0
  2. Q8 0
  3. Q 0
  4. Q2 0
AIPMT 2000
5

Electric field at centre O of semicircle of radius a having linear charge density is given as [figure]

  1. 2 0 a
  2. 0 a
  3. 2 0 a
  4. 0 a
AIPMT 2000

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