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Oscillations · Question 58

AIPMT 2000MCQEasy📈 Topic in 38% papers+4−1
1

Two masses MA and MB are hung from two strings of length lA and lB respectively. They are executing SHM with frequency relation fA = 2fB, then relation

  1. lA = lB4, does not depend on mass
  2. lA = 4lB, does not depend on mass
  3. lA = 2lB and MA = 2MB
  4. lA = lB2 and MA = MB2

Answer

(1) lA = lB4, does not depend on mass

Solution

For a simple pendulum, f = 12 gl, which does not depend on the mass of the bob.

fAfB = lBlA

2 = lBlA

lA = lB4 (independent of mass)

Answer: (1)

AIPMT 2000

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2

The bob of simple pendulum having length l, is displaced from mean position to an angular position with respect to vertical. If it is released, then velocity of bob at equilibrium position

  1. 2gl(1 - )
  2. 2gl(1 + )
  3. 2gl
  4. 2gl
AIPMT 2000
3

The equations of two waves acting in perpendicular directions are given as x = a ( t + ) and y = a ( t + ), where = + 2, the resultant wave represents

  1. a parabola
  2. a circle
  3. an ellipse
  4. a straight line
AIPMT 2000

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