In the reaction 21H + 31H 42He + 10n, if the binding energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is
- a + b + c
- a + b - c
- c - a - b
- c + a - b
Answer
(3) c - a - b
Solution
Energy released = (total binding energy of products) − (total binding energy of reactants)
The free neutron 10n has zero binding energy.
Q = c - (a + b)
Q = c - a - b
Answer: (3)