1
A particle is projected making an angle of 45 with horizontal having kinetic energy K. The kinetic energy at highest point will be
- K 2
- K2
- 2K
- K
Answer
(2) K2
Solution
At the highest point only the horizontal velocity u 45 remains.
K' = 12m(u 45 )2 = 12mu2 2 45
= K 12 = K2
Answer: (2)
AIPMT 2001