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Surface Chemistry

Previous year questions with solutions · 2019 – 2026

3Questions
3Papers covered
2.94% ↓5.9%Weightage in 2026
’24
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
2026120.52.94% ↓5.9%
2025120.53.12% ↑6.2%
2024120.52.94%

3 questions · newest paper first

1

At a given temperature, 0.45 g of acetic acid in 50 mL of water is shaken with 1.0 g of charcoal and the pH of the resulting solution is 3.0. Assume, the adsorption of acetic acid from the aqueous solution by charcoal follows Freundlich isotherm, xm=kC1/n If the plot of 10(x/m) against 10C gives a straight line with slope 1, the value of k in L mol-1 is . Given: The molar mass of acetic acid is 60 g mol-1. The acid dissociation constant of acetic acid is 1.0 10-5 at the given temperature. x is the mass (in grams) of acetic acid adsorbed. m is the mass (in grams) of charcoal. C is the equilibrium concentration of acetic acid in the solution after the adsorption is complete. k and n are constants for acetic acid–charcoal system at the given temperature.

JEE Advanced 2026 Paper 2
2

Adsorption of phenol from its aqueous solution on to fly ash obeys Freundlich isotherm. At a given temperature, from 10 mg g-1 and 16 mg g-1 aqueous phenol solutions, the concentrations of adsorbed phenol are measured to be 4 mg g-1 and 10 mg g-1, respectively. At this temperature, the concentration (in mg g-1) of adsorbed phenol from 20 mg g-1 aqueous solution of phenol will be . Use: 10 2 = 0.3

JEE Advanced 2025 Paper 2
3

To form a complete monolayer of acetic acid on 1g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies P 10-23 m2 surface area on charcoal, the value of P is . [Use given data: Surface area of charcoal = 1.5 102 m2 g-1; Avogadro’s number (NA) = 6.0 1023 mol-1]

JEE Advanced 2024 Paper 2