Consider a data consisting of 10 observations x1,x2, ,x10, whose mean is 5 and variance is 7. If the mean and the variance of the first 8 observations x1,x2, ,x8 are 4 and 3.5, respectively, and x9<x10, then the value of 3x9+2x10 is .
Statistics
Previous year questions with solutions · 2024 – 2026
2Questions
2Papers covered
2.94% ↓5.9%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 1 | 2 | 0.5 | 2.94% ↓5.9% |
| 2025 | 1 | 2 | 0.5 | 3.12% |
1
JEE Advanced 2026 Paper 2
2
Consider the following frequency distribution: array|c|c|c|c|c|c|c|c| Value & 4 & 5 & 8 & 9 & 6 & 12 & 11 \ Frequency & 5 & f1 & f2 & 2 & 1 & 1 & 3 \ array Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6. For the given frequency distribution, let denote the mean deviation about the mean, denote the mean deviation about the median, and 2 denote the variance. Match each entry in List-I to the correct entry in List-II and choose the correct option.
- (P) → (5), (Q) → (3), (R) → (2), (S) → (4)
- (P) → (5), (Q) → (2), (R) → (3), (S) → (1)
- (P) → (5), (Q) → (3), (R) → (2), (S) → (1)
- (P) → (3), (Q) → (2), (R) → (5), (S) → (4)
JEE Advanced 2025 Paper 1