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The value of the definite integral 02 13x+3 dx is
- 12
- 13
- e 33
- e 32
JEE Advanced 2026 Paper 2
Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 1 | 2 | 0.5 | 2.94% ↓5.9% |
| 2025 | 1 | 2 | 0.5 | 3.12% ↓64.6% |
| 2024 | 3 | 2 | 1.5 | 8.82% |
The value of the definite integral 02 13x+3 dx is
If = 122 -1x2x2-3x+2 dx, then the value of 7 ( 2 7 ) is . (Here, the inverse trigonometric function -1x assumes values in (- 2, 2 ).)
Let the function f:[1, ) R be defined by f(t)= cases(-1)n+12, & if t=2n-1, n N,\ (2n+1-t)2f(2n-1)+ (t-(2n-1))2f(2n+1), & if 2n-1<t<2n+1, n N. cases Define g(x)= 1xf(t) dt, x (1, ). Let denote the number of solutions of the equation g(x)=0 in the interval (1,8] and = x 1+ g(x)x-1. Then the value of + is equal to .
The value of 2 0 2f(x)g(x) dx- 0 2g(x) dx is .
The value of 16 3 0 2f(x)g(x) dx is .