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The difference in the capacitance (in F) between the metal plates at t=0 and that at t=500 s is (8-n) 0, where 0 is the permittivity of free space. The value of n is:
JEE Advanced 2026 Paper 2
Previous year questions with solutions · 2024 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 2 | 2 | 1 | 5.88% ↑88.2% |
| 2025 | 1 | 2 | 0.5 | 3.12% ↓46.9% |
| 2024 | 2 | 2 | 1 | 5.88% |
The difference in the capacitance (in F) between the metal plates at t=0 and that at t=500 s is (8-n) 0, where 0 is the permittivity of free space. The value of n is:
An infinitely long thin wire, having a uniform charge density per unit length of 5 nC/m, is passing through a spherical shell of radius 1 m, as shown in the figure. A 10 nC charge is distributed uniformly over the spherical shell. If the configuration of the charges remains static, the magnitude of the potential difference between points P and R, in Volt, is . [Given: In SI units 14 0 = 9 109, 2 = 0.7. Ignore the area pierced by the wire.] [figure]