Structure of Atom

If shortest wavelength of hydrogen atom in Lyman series is x, then longest wavelength in Balmer series of He+ is:

1. 9x5
2. 36x5
3. x4
4. 5x9

What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?

1. 5 : 1
2. 5 : 0.81
3. 5 : 1.75
4. 5 : 27

The wave numbers of three spectral lines of H atom are considered. Identify the set of spectral lines belonging to Balmer series. (R = Rydberg constant)

1. 5R36, 3R16, 21R100
2. 7R144, 3R16, 16R255
3. 3R4, 3R16, 7R144
4. 5R36, 8R9, 15R16

The hydrogen spectrum consists of several spectral lines in Lyman series (L1, L2, L3 ; L1 has lowest energy among Lyman series). Similarly it consists of several spectral lines in Balmer series (B1, B2, B3 ; B1 has lowest energy among Balmer lines). The energy of L1 is x times the energy of B1. The value of x is 10-1. (Nearest integer)

The wavelength of spectral line obtained in the spectrum of Li2+ ion, when the transition takes place between two levels whose sum is 4 and difference is 2, is

1. 1.14 10-6 cm
2. 2.28 10-6 cm
3. 1.14 10-7 cm
4. 2.28 10-7 cm

The energy of first (lowest) Balmer line of H atom is x J. The energy (in J) of second Balmer line of H atom is :

1. x1.35
2. 1.35x
3. x2
4. 2x

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

1. Both Statement I and Statement II are true
2. Statement I is true but Statement II is false
3. Statement I is false but Statement II is true
4. Both Statement I and Statement II are false

Consider the following spectral lines for atomic hydrogen : The correct arrangement of the above lines in ascending order of energy is :

1. D < C < A < B
2. A < B < C < D
3. D < A < C < B
4. C < D < B < A