The energy of first (lowest) Balmer line of H atom is x J. The energy (in J) of second Balmer line of H atom is :
- x1.35
- 1.35x
- x2
- 2x
Answer
(2) 1.35x
Solution
For the Balmer series (n1 = 2): E ( 122 - 1n22 )
First line (n2 = 3): 14 - 19 = 536
Second line (n2 = 4): 14 - 116 = 316
E2E1 = 3/165/36 = 10880 = 1.35
E2 = 1.35x J
Answer: (2)