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Previous year questions with solutions · 2025 – 2026

92Questions
31Papers covered
11.58% ↓6.1%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
202655192.911.58% ↓6.1%
202537123.112.33%

20 questions · newest paper first

1

Let x2f (a2+7a+3 )+ y2f(3a+15)=1 represent an ellipse with major axis along y-axis, where f is a strictly decreasing positive function on R. If the set of all possible values of a is R-[ , ], then 2+ 2 is equal to :

  1. 28
  2. 40
  3. 61
  4. 24
JEE Main 2026 (Online) 8th April Evening Shift
2

Let a focus of the ellipse E : x2a2+ y2b2=1 be S(4, 0) and its eccentricity be 45. If the point P(3, ) lies on E and O is the origin, then the area of POS is equal to:

  1. 125
  2. 145
  3. 245
  4. 485
JEE Main 2026 (Online) 5th April Morning Shift
3

Consider the parabola P : y2=4kx and the ellipse E : x2a2+ y2b2=1. Let the line segment joining the points of intersection of P and E, be their latus rectums. If the eccentricity of E is e, then e2+2 2 is equal to .

JEE Main 2026 (Online) 4th April Morning Shift
4

Let an ellipse x2a2+ y2b2=1, a<b, pass through the point (4, 3) and have eccentricity 53. Then the length of its latus rectum is :

  1. 4 53
  2. 2 5
  3. 7 53
  4. 8 53
JEE Main 2026 (Online) 2nd April Morning Shift
5

An ellipse has its center at (1, -2), one focus at (3, -2) and one vertex at (5, -2). Then the length of its latus rectum is :

  1. 6
  2. 6 3
  3. 16 3
  4. 4 3
JEE Main 2026 (Online) 28th January Evening Shift
6

Let each of the two ellipses E1: x2a2 + y2b2 = 1, (a > b) and E2: x2A2 + y2B2 = 1, (A < B) have eccentricity 45. Let the lengths of the latus recta of E1 and E2 be l1 and l2, respectively, such that 2l12 = 9l2. If the distance between the foci of E1 is 8, then the distance between the foci of E2 is

  1. 965
  2. 85
  3. 165
  4. 325
JEE Main 2026 (Online) 24th January Morning Shift
7

Let the length of the latus rectum of an ellipse x2a2 + y2b2 = 1, (a > b), be 30. If its eccentricity is the maximum value of the function f(t) = - 34 + 2t - t2, then (a2 + b2) is equal to

  1. 276
  2. 516
  3. 256
  4. 496
JEE Main 2026 (Online) 24th January Evening Shift
8

Let the line y - x = 1 intersect the ellipse x22 + y21 = 1 at the points A and B. Then the angle made by the line segment AB at the center of the ellipse is :

  1. - -1 ( 14 )
  2. 2 + -1 ( 14 )
  3. 2 + 2 -1 ( 14 )
  4. 2 - -1 ( 14 )
JEE Main 2026 (Online) 23rd January Morning Shift
9

Let S and S′ be the foci of the ellipse x225 + y29 = 1 and P( , ) be a point on the ellipse in the first quadrant. If (SP)2 + (S'P)2 - SP S'P = 37, then 2 + 2 is equal to :

  1. 13
  2. 15
  3. 11
  4. 17
JEE Main 2026 (Online) 22nd January Evening Shift
10

Let the ellipse 3x2 + py2 = 4 pass through the centre C of the circle x2 + y2 - 2x - 4y - 11 = 0 of radius r. Let f1, f2 be the focal distances of the point C on the ellipse. Then 6f1f2 - r is equal to

  1. 78
  2. 68
  3. 70
  4. 74
JEE Main 2025 (Online) 8th April Evening Shift
11

Let the length of a latus rectum of an ellipse x2a2 + y2b2 = 1 be 10. If its eccentricity is the minimum value of the function f(t) = t2 + t + 1112, t R, then a2 + b2 is equal to :

  1. 115
  2. 120
  3. 125
  4. 126
JEE Main 2025 (Online) 7th April Evening Shift
12

Let p be the number of all triangles that can be formed by joining the vertices of a regular polygon P of n sides and q be the number of all quadrilaterals that can be formed by joining the vertices of P. If p + q = 126, then the eccentricity of the ellipse x216 + y2n = 1 is :

  1. 1 2
  2. 12
  3. 74
  4. 34
JEE Main 2025 (Online) 7th April Evening Shift
13

The length of the latus-rectum of the ellipse, whose foci are (2, 5) and (2, -3) and eccentricity is 45, is

  1. 503
  2. 185
  3. 65
  4. 103
JEE Main 2025 (Online) 4th April Morning Shift
14

The centre of a circle C is at the centre of the ellipse E: x2a2 + y2b2 = 1, a > b. Let C pass through the foci F1 and F2 of E such that the circle C and the ellipse E intersect at four points. Let P be one of these four points. If the area of the triangle PF1F2 is 30 and the length of the major axis of E is 17, then the distance between the foci of E is :

  1. 12
  2. 26
  3. 13
  4. 132
JEE Main 2025 (Online) 4th April Evening Shift
15

A line passing through the point P( 5, 5) intersects the ellipse x236 + y225 = 1 at A and B such that (PA) (PB) is maximum. Then 5 (PA2 + PB2 ) is equal to :

  1. 290
  2. 377
  3. 338
  4. 218
JEE Main 2025 (Online) 3rd April Morning Shift
16

Let C be the circle of minimum area enclosing the ellipse E : x2a2 + y2b2 = 1 with eccentricity 12 and foci ( 2, 0). Let PQR be a variable triangle, whose vertex P is on the circle C and the side QR of length 2a is parallel to the major axis of E and contains the point of intersection of E with the negative y-axis. Then the maximum area of the triangle PQR is :

  1. 8(3 + 2)
  2. 8(2 + 3)
  3. 6(3 + 2)
  4. 6(2 + 3)
JEE Main 2025 (Online) 3rd April Evening Shift
17

If S and S′ are the foci of the ellipse x218 + y29 = 1 and P be a point on the ellipse, then (SP S'P) + (SP S'P) is equal to :

  1. 3(6 + 2)
  2. 3(1 + 2)
  3. 27
  4. 9
JEE Main 2025 (Online) 2nd April Morning Shift
18

If the length of the minor axis of an ellipse is equal to one fourth of the distance between the foci, then the eccentricity of the ellipse is :

  1. 3 19
  2. 316
  3. 4 17
  4. 57
JEE Main 2025 (Online) 2nd April Evening Shift
19

Let the ellipse E1 : x2a2 + y2b2 = 1, a > b and E2 : x2A2 + y2B2 = 1, A < B have same eccentricity 1 3. Let the product of their lengths of latus rectums be 32 3 and the distance between the foci of E1 be 4. If E1 and E2 meet at A, B, C and D, then the area of the quadrilateral ABCD equals :

  1. 24 65
  2. 18 65
  3. 6 6
  4. 12 65
JEE Main 2025 (Online) 29th January Morning Shift
20

Let E1 : x29 + y24 = 1 be an ellipse. Ellipses Ei's are constructed such that their centres and eccentricities are same as that of E1, and the length of minor axis of Ei is the length of major axis of Ei+1 (i 1). If Ai is the area of the ellipse Ei, then 5 ( i=1 Ai ), is equal to .

JEE Main 2025 (Online) 28th January Morning Shift