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Conic Sections · Question 35

JEE Main 2026 (Online) 24th January Morning ShiftMCQMedium📈 Topic in 61% papers+4−1
1

Let each of the two ellipses E1: x2a2 + y2b2 = 1, (a > b) and E2: x2A2 + y2B2 = 1, (A < B) have eccentricity 45. Let the lengths of the latus recta of E1 and E2 be l1 and l2, respectively, such that 2l12 = 9l2. If the distance between the foci of E1 is 8, then the distance between the foci of E2 is

  1. 965
  2. 85
  3. 165
  4. 325

Answer

(4) 325

Solution

For E1 (major axis along x-axis): 2ae = 8 2a ( 45 ) = 8 a = 5

b2 = a2(1 - e2) = 25 (1 - 1625 ) = 9

l1 = 2b2a = 185

2l12 = 9l2 2 32425 = 9l2 l2 = 7225

For E2 (A < B, major axis along y-axis): A2 = B2(1 - e2) = 925B2

l2 = 2A2B = 18B25 = 7225 B = 4

distance between the foci of E2 = 2Be = 2 4 45 = 325

Answer: (4)

JEE Main 2026 (Online) 24th January Morning Shift

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2

Let the image of parabola x2 = 4y, in the line x - y = 1 be (y + a)2 = b(x - c), a, b, c N. Then a + b + c is equal to

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3

Let the length of the latus rectum of an ellipse x2a2 + y2b2 = 1, (a > b), be 30. If its eccentricity is the maximum value of the function f(t) = - 34 + 2t - t2, then (a2 + b2) is equal to

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4

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Let the domain of the function f(x) = 3 5 7 (9x - x2 - 13 ) be the interval (m, n). Let the hyperbola x2a2 - y2b2 = 1 have eccentricity n3 and the length of the latus rectum 8m3. Then b2 - a2 is equal to :

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  1. - -1 ( 14 )
  2. 2 + -1 ( 14 )
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7

Let PQ be a chord of the hyperbola x24 - y2b2 = 1, perpendicular to the x-axis such that OPQ is an equilateral triangle, O being the centre of the hyperbola. If the eccentricity of the hyperbola is 3, then the area of the triangle OPQ is

  1. 2 3
  2. 115
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  4. 95
JEE Main 2026 (Online) 23rd January Evening Shift
8

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  1. 53
  2. 52
  3. 55
  4. 51
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An equilateral triangle OAB is inscribed in the parabola y2 = 4x with the vertex O at the vertex of the parabola. Then the minimum distance of the circle having AB as a diameter from the origin is

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10

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  1. 0.6
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11

Let the set of all values of r, for which the circles (x+1)2 + (y+4)2 = r2 and x2 + y2 - 4x - 2y - 4 = 0 intersect at two distinct points be the interval ( , ). Then is equal to

  1. 21
  2. 24
  3. 20
  4. 25
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