The average thermal energy for a mono-atomic gas is : (kB is Boltzmann constant and T absolute temperature)
- 32kBT
- 52kBT
- 72kBT
- 12kBT
Answer
(1) 32kBT
Solution
A mono-atomic gas molecule has only 3 translational degrees of freedom.
As per the law of equipartition of energy, each degree of freedom has average energy 12kBT.
∴ Average thermal energy = 3 12kBT = 32kBT
Answer: (1)