PYQSide ExamsMy practice

Isomerism · Question 39

AIPMT 2000MCQEasy📈 Topic in 12% papers+4−1
1

2-Butene shows geometrical isomerism due to

  1. restricted rotation about double bond
  2. free rotation about double bond
  3. free rotation about single bond
  4. chiral carbon

Answer

(1) restricted rotation about double bond

Solution

∵ A carbon–carbon double bond consists of one σ-bond and one π-bond; rotation about it would break the sideways overlap of the p-orbitals forming the π-bond.

⇒ Rotation about C=C is restricted, so the groups on the doubly bonded carbons stay fixed in space.

In 2-butene (CH3-CH=CH-CH3) each doubly bonded carbon carries two different groups (H and CH3).

∴ As per NCERT, 2-butene exists as cis and trans isomers (geometrical isomerism) because of restricted rotation about the double bond.

Answer: (1)

AIPMT 2000

Keep practising — Isomerism

2

Dihedral angle in staggered form of ethane is

  1. 0
  2. 120
  3. 60
  4. 180
AIPMT 2000

All Isomerism PYQs →

PDFDownload Isomerism PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Chemistry chapters