In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMnO4 solution. If the volume of KMnO4 solution required to reach end point is 10 mL, the strength of the KMnO4 solution is
- 0.15 M
- 0.10 M
- 0.20 M
- 0.25 M
Previous year questions with solutions · 2000 – 2026
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 2 | 2 | 1 | 2.22% →0% |
| 2025 | 1 | 1 | 1 | 2.22% ↑124.4% |
| 2024 | 1 | 2 | 0.5 | 0.99% ↓49.5% |
| 2023 | 1 | 1 | 1 | 1.96% ↑98% |
| 2022 | 1 | 2 | 0.5 | 0.99% ↓50.5% |
| 2021 | 1 | 1 | 1 | 2.00% ↓10% |
| 2020 | 1 | 1 | 1 | 2.22% →0% |
| 2019 | 1 | 1 | 1 | 2.22% ↓66.7% |
| 2018 | 3 | 1 | 3 | 6.67% ↑200% |
| 2015 | 2 | 2 | 1 | 2.22% ↓50% |
| 2014 | 2 | 1 | 2 | 4.44% ↑18.5% |
| 2012 | 3 | 2 | 1.5 | 3.75% ↑91.3% |
| 2009 | 1 | 1 | 1 | 1.96% →0% |
| 2008 | 1 | 1 | 1 | 1.96% ↓5.9% |
| 2004 | 1 | 1 | 1 | 2.08% ↑2.1% |
| 2003 | 1 | 1 | 1 | 2.04% ↑2% |
| 2002 | 1 | 1 | 1 | 2.00% ↑2% |
| 2000 | 1 | 1 | 1 | 1.96% |
In an acidic medium, 10 mL of 0.25 M oxalic acid is titrated with KMnO4 solution. If the volume of KMnO4 solution required to reach end point is 10 mL, the strength of the KMnO4 solution is
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