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Structure of Atom

JEE Main 2025 (Online) 23rd January Morning ShiftMCQMedium📈 Topic in 24% papers+4−1
Ques. 1JEE Main 2025, 23 January (Morning Shift)

Heat treatment of muscular pain involves radiation of wavelength of about 900 nm. Which spectral line of H atom is suitable for this? Given : Rydberg constant RH = 105 cm-1, h = 6.6 10-34 J s, c = 3 108 m/s

  1. Lyman series, 1
  2. Balmer series, 2
  3. Paschen series, 5 3
  4. Paschen series, 3

Answer

(4) Paschen series, 3

Solution

Concept: 1 = RH ( 1n12 - 1n22 ), = 9 10-5 cm

1 RH = 19 10-5 105 = 19 ⇒ n1 = 3, n2 =

∴ Paschen series, 3

Answer: (4)

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Ques. 2JEE Main 2025, 23 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is false but Statement II is true
  4. Statement I is true but Statement II is false
Ques. 3JEE Main 2025, 23 January (Evening Shift)

Given below are two statements about X-ray spectra of elements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are false
Ques. 4JEE Main 2025, 22 January (Morning Shift)

Radius of the first excited state of Helium ion is given as : a0 radius of first stationary state of hydrogen atom.

  1. r = a04
  2. r = 2a0
  3. r = 4a0
  4. r = a02
Ques. 5JEE Main 2025, 22 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is false but Statement II is true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are true
Ques. 6JEE Main 2025, 22 January (Evening Shift)

Niobium (Nb) and ruthenium (Ru) have “x” and “y” number of electrons in their respective 4 d orbitals. The value of x+y is .

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