A wire carrying a current I along the positive x-axis has length L. It is kept in a magnetic field B = (2 i + 3 j - 4 k) T. The magnitude of the magnetic force acting on the wire is :
- 5 IL
- 5 IL
- 3 IL
- 3 IL
Answer
(2) 5 IL
Solution
F = I L B with L = L i
F = IL i (2 i + 3 j - 4 k)
F = IL(0 + 3 k + 4 j) (since i j = k, i k = - j)
| F| = IL 42 + 32 = 5 IL
Answer: (2)