The magnetic field on the axis of a circular loop of radius 100 cm carrying current I = 2 A, at point 1 m away from the centre of the loop is given by :
- 6.28 10-4 T
- 3.14 10-7 T
- 6.28 10-7 T
- 3.14 10-4 T
Answer
(2) 3.14 10-7 T
Solution
Field on the axis of a circular loop:
B = 0 I R22(R2 + x2)3/2
Here R = 1 m, x = 1 m, I = 2 A
B = 4 10-7 2 12 (2)3/2
= 4 10-7 24 2
= 10-7
B = 3.14 10-7 T
Answer: (2)