A force F= + x2 acts on an object in the x-direction. The work done by the force is 5 J when the object is displaced by 1 m. If the constant =1 N then will be
- 15 N/m2
- 10 N/m2
- 12 N/m2
- 8 N/m2
Answer
(3) 12 N/m2
Solution
Work = area under the F–x graph: W= 01( + x2) dx
[figure]
= + 3=1+ 3=5
=12 N/m2
Answer: (3)