PYQSidePowered byPrepblink ExamsMy practice

Work, Energy and Power

JEE Main 2024 (Online) 29th January Evening ShiftMCQEasy📈 Topic in 21% papers+4−1
Ques. 1JEE Main 2024, 29 January (Evening Shift)

The bob of a pendulum was released from a horizontal position. The length of the pendulum is 10 m. If it dissipates 10\% of its initial energy against air resistance, the speed with which the bob arrives at the lowest point is: [Use, g=10 m s-2]

  1. 5 6 m s-1
  2. 5 5 m s-1
  3. 2 5 m s-1
  4. 6 5 m s-1

Answer

(4) 6 5 m s-1

Solution

Initial energy (w.r.t. lowest point): E=mgl

90% of E is left at the lowest point:

12mv2= 910mgl

v2=2 910 10 10=180

v= 180=6 5 m s-1

The bob falls through a height equal to the length l; 10% of this energy is lost.

Answer: (4)

Keep practising — Work, Energy and Power

Ques. 2JEE Main 2024, 27 January (Morning Shift)

Two bodies of mass 4 g and 25 g are moving with equal kinetic energies. The ratio of magnitude of their linear momentum is :

  1. 3:5
  2. 5:4
  3. 2:5
  4. 4:5
Ques. 3JEE Main 2024, 27 January (Evening Shift)

A ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle ( ) of thread deflection in the extreme position will be :

  1. -1 ( 12 )
  2. 2 -1 ( 12 )
  3. 2 -1 ( 1 5 )
  4. -1 ( 2 )

All Work, Energy and Power PYQs →

PDFDownload Work, Energy and Power PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters