PYQSidePowered byPrepblink ExamsMy practice

Work, Energy and Power

JEE Main 2024 (Online) 29th January Evening ShiftMCQMedium📈 Topic in 14% papers+4−1
Ques. 1JEE Main 2024, 29 January (Evening Shift)

A bob of mass 'm' is suspended by a light string of length 'L'. It is imparted a minimum horizontal velocity at the lowest point A such that it just completes half circle reaching the top most position B. The ratio of kinetic energies (K.E)A(K.E)B is : [figure]

  1. 5 : 1
  2. 3 : 2
  3. 1 : 5
  4. 2 : 5

Answer

(1) 5 : 1

Solution

Just reaching the top B tension TB=0:

mg= mVH2L VH2=gL

Energy conservation A B: 12mVL2= 12mVH2+mg(2L)

VL2=gL+4gL=5gL

(K.E)A(K.E)B= VL2VH2= 5gLgL=5:1

At the top only gravity supplies the centripetal force when the speed is minimum.

Answer: (1)

Keep practising — Work, Energy and Power

Ques. 2JEE Main 2024, 29 January (Evening Shift)

The bob of a pendulum was released from a horizontal position. The length of the pendulum is 10 m. If it dissipates 10\% of its initial energy against air resistance, the speed with which the bob arrives at the lowest point is: [Use, g=10 m s-2]

  1. 5 6 m s-1
  2. 5 5 m s-1
  3. 2 5 m s-1
  4. 6 5 m s-1
Ques. 3JEE Main 2024, 27 January (Morning Shift)

Two bodies of mass 4 g and 25 g are moving with equal kinetic energies. The ratio of magnitude of their linear momentum is :

  1. 3:5
  2. 5:4
  3. 2:5
  4. 4:5
Ques. 4JEE Main 2024, 27 January (Evening Shift)

A ball suspended by a thread swings in a vertical plane so that its magnitude of acceleration in the extreme position and lowest position are equal. The angle ( ) of thread deflection in the extreme position will be :

  1. -1 ( 12 )
  2. 2 -1 ( 12 )
  3. 2 -1 ( 1 5 )
  4. -1 ( 2 )

All Work, Energy and Power PYQs →

PDFDownload Work, Energy and Power PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters