A wire of length L and radius r is clamped at one end. If its other end is pulled by a force F, its length increases by l. If the radius of the wire and the applied force both are reduced to half of their original values keeping original length constant, the increase in length will become:
- 2 times
- 4 times
- 3 times
- 32 times
Answer
(1) 2 times
Solution
Y= FL r2 l l= FL r2Y Fr2
l'l= F/2(r/2)2 r2F= 1/21/4=2
Same material and length, so Y and L do not change.
Answer: (1)