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If x 0 ( xx ) 1x2 = p, then 96 e p is equal to
32
The limit is of the form 1 :
p = eL, where L = x 0 1x2 ( xx - 1 ) = x 0 x - xx3
∵ x = x + x33 + 2x515 +
⇒ L = x 0 ( 13 + 2x215 + ) = 13
⇒ p = e1/3
∴ 96 e p = 96 13 = 32
Answer: 32
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