The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are
- 10 cm, 10 cm
- 15 cm, 5 cm
- 18 cm, 2 cm
- 11 cm, 9 cm
Answer
(3) 18 cm, 2 cm
Solution
For normal adjustment (parallel rays):
m = fofe = 9 fo = 9fe
L = fo + fe = 20 cm
9fe + fe = 20 fe = 2 cm
fo = 18 cm
Answer: (3)