A bag contains 6 blue and 6 green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue and one green ball is :
- 63925
- 17231
- 16231
- 64925
Answer
(3) 16231
Solution
When k blue and k green balls remain, the probability that the next pair has one ball of each colour
= kC1 kC12kC2= k2k(2k-1)= k2k-1
After such a draw, k-1 balls of each colour remain, so take k=6, 5, 4, 3, 2, 1 in turn:
P= 611 59 47 35 23 11
P= 72010395= 16231
Answer: (3)