Consider the matrices : A = bmatrix 2 & -5 \ 3 & m bmatrix, B = bmatrix 20 \ m bmatrix and X = bmatrix x \ y bmatrix. Let the set of all m, for which the system of equations AX = B has a negative solution (i.e., x < 0 and y < 0), be the interval (a, b). Then 8 ab |A| dm is equal to .
Answer
450
Solution
AX = B gives 2x - 5y = 20 and 3x + my = m, with |A| = 2m + 15.
By Cramer's rule: x = 20m + 5m2m + 15 = 25m2m + 15 and y = 2m - 602m + 15
x < 0 gives - 152 < m < 0
y < 0 gives - 152 < m < 30
So both hold for m (- 152, 0 ) = (a, b)
8 -15/20(2m + 15) dm = 8 [m2 + 15m ]-15/20
= 8 [0 - ( 2254 - 2252 ) ] = 8 2254 = 450
Answer: 450