When three identical bulbs of 60 watt, 200 volt rating are connected in series to a 200 volt supply, the power drawn by them will be
- 60 watt
- 180 watt
- 10 watt
- 20 watt
Answer
(4) 20 watt
Solution
Resistance of one bulb: R = V2P = (200)260
In series: Rs = 3R
P = V23R = 13 (200)2R = 603
P = 20 W
Answer: (4)