Water flows through a horizontal tube as shown in the figure. The difference in height between the water columns in vertical tubes is 5 cm and the area of cross-sections at A and B are 6 cm2 and 3 cm2 respectively. The rate of flow will be cm3/s. (take g = 10 m/s2) [figure]
- 100 3
- 200 3
- 200 6
- 200 3
Answer
(4) 200 3
Solution
Let vA and vB be the speeds at A and B (A1 = 6 cm2, A2 = 3 cm2).
Equation of continuity: A1 vA = A2 vB vB = 2vA
Bernoulli's theorem for the horizontal tube: PA - PB = 12 (vB2 - vA2)
The pressure difference is shown by the height difference h of the columns: PA - PB = gh
gh = 12(4vA2 - vA2) = 32vA2
vA = 2gh3 = 2 1000 53 = 100 3 cm/s (taking g = 1000 cm/s2)
Rate of flow = A1 vA = 6 100 3 = 600 3
Rate of flow = 200 3 cm3/s
Answer: (4)