Surface tension of two liquids (having same densities), T1 and T2, are measured using capillary rise method utilizing two tubes with inner radii of r1 and r2 where r1 > r2. The measured liquid heights in these tubes are h1 and h2 respectively. [Ignore the weight of the liquid above the lowest point of meniscus]. The heights h1 and h2 and surface tensions T1 and T2 satisfy the relation :
- h1 > h2 and T1 = T2
- h1 < h2 and T1 = T2
- h1 > h2 and T1 < T2
- h1 = h2 and T1 = T2
Answer
(2) h1 < h2 and T1 = T2
Solution
Capillary rise: h = 2T r g
T = hr g2 , i.e. T hr (same , same )
If T1 = T2: h1 r1 = h2 r2; since r1 > r2 h1 < h2 (option 2)
Option (1) and (4): with T1 = T2, h1 h2 is impossible because r1 > r2.
Option (3): h1 > h2 and r1 > r2 give h1 r1 > h2 r2 T1 > T2, not T1 < T2.
the only possible relation is h1 < h2 and T1 = T2.
Answer: (2)