A proton and an electron are associated with same de-Broglie wavelength. The ratio of their kinetic energies is: (Assume h = 6.63 10-34 J s, me = 9.0 10-31 kg and mp = 1836 times me)
- 1 : 11836
- 1 : 1836
- 1 : 1836
- 1 : 1 1836
Answer
(3) 1 : 1836
Solution
= hp, so the same means the same momentum p.
K = p22m K 1m (p fixed)
KpKe = memp = 11836
Kp : Ke = 1 : 1836
Answer: (3)