Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light (I1<I2) of same wavelengths :
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(3) [figure]
Solution
Stopping potential depends only on the frequency: eV0=h - 0
same wavelength same -V0 for both curves
Saturation current intensity; I2>I1 I2 curve lies higher
(A): I2 starts at V=0, not at -V0 (A) is wrong
(B): I2 and I1 start at different stopping potentials (B) is wrong
(C): common -V0, I2 above I1 (C) is correct
(D): different stopping potentials (D) is wrong
Answer: (3)