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Statistics

JEE Main 2024 (Online) 30th January Evening ShiftNumericalEasy📈 Topic in 45% papers+4
Ques. 1JEE Main 2024, 30 January (Evening Shift)

The variance 2 of the data [figure] is .

Answer

29

Solution

fi=22, fixi=0+2+15+12+60+36+51=176 x= 17622=8

fixi2=0+2+75+72+600+432+867=2048

2= fixi2 fi- x2= 204822-64

= 32011 29.09 29 (nearest integer)

Answer: 29

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Ques. 2JEE Main 2024, 29 January (Morning Shift)

If the mean and variance of the data 65,68,58,44,48,45,60, , ,60 where > , are 56 and 66.2 respectively, then 2+ 2 is equal to .

Ques. 3JEE Main 2024, 29 January (Evening Shift)

If the mean and variance of five observations are 245 and 19425 respectively and the mean of the first four observations is 72, then the variance of the first four observations is equal to

  1. 54
  2. 45
  3. 1054
  4. 7712
Ques. 4JEE Main 2024, 27 January (Morning Shift)

Let a1, a2, a10 be 10 observations such that k=110 ak=50 and k<j ak aj=1100. Then the standard deviation of a1, a2, , a10 is equal to :

  1. 5
  2. 115
  3. 10
  4. 5
Ques. 5JEE Main 2024, 27 January (Evening Shift)

The mean and standard deviation of 15 observations were found to be 12 and 3 respectively. On rechecking it was found that an observation was read as 10 in place of 12 . If and 2 denote the mean and variance of the correct observations respectively, then 15 ( + 2+ 2 ) is equal to .

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