The diffraction pattern of a light of wavelength 400 nm diffracting from a slit of width 0.2 mm is focused on the focal plane of a convex lens of focal length 100 cm. The width of the 1st secondary maxima will be :
- 2 mm
- 0.2 mm
- 0.02 mm
- 2 cm
Answer
(1) 2 mm
Solution
Minima: a =n ; a secondary maximum lies between two successive minima
width of a secondary maximum = fa
= 400 10-9 10.2 10-3 m
=2 10-3 m=2 mm
Answer: (1)